# A particle with a mass of 6.64x10^–27 kg and a charge of+3.20x10^–19 C is accelerated from rest through a potential difference of 2.45x10^6 V.

1. A particle with a mass of 6.64x10^–27 kg and a charge of+3.20x10^–19 C is accelerated from rest through a potential difference of 2.45x10^6 V. The particle then enters a uniform1.60-T magnetic field. If the particle’s velocity is perpendicular to the magnetic field at all times, what is the magnitude of the magnetic force exerted on the particle?

2. Determine the currents in the resistors for the circuit. E1=25.0 V, E2= 6.0 V, E3= 6.0V, Ra= 6.0 ohms, Rb= 3.0 ohms, Rc= 5.0ohms, Rd= 10.0 ohms, Re= 6.0 ohms

• Posted: 2 months ago
Solution

Purchase the answer to view it Save time and money!
Our teachers already did such homework, use it as a reference! • Not rated

### A particle with a mass of 6.64x10^–27 kg and a charge of+3.20x10^–19 C is accelerated from rest through a potential difference of 2.45x10^6 V.

1. A particle with a mass of 6.64x10^–27 kg and a charge of+3.20x10^–19 C is accelerated from rest through a potential difference of 2.45x10^6 V. The particle then enters a uniform1.60-T …