# Math3a

**maurog**

Let's say you want to build a square ice rink in your backyard for your children. You have budgeted to use 800 ft^{3} of water, and the ice must be 0.5 ft thick. What are the dimensions of the ice rink?

The volume of the rink would be V = l*w*h. Because we know the planned volume and depth, we can substitute into the equation to give 800 = l*w*(0.5)

We also know that the rink should be square, so length and width are equal. Therefore, we can say that 800 = w*w(0.5). Simplified, the equation becomes 0.5w^{2 } = 800.

Class,

How do we use radicals to solve for the dimensions of the ice rink?

What other real world uses are there for radicals?

Must be step by step!

- 6 years ago
- 2.5

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