# Intro statistics homework

1. Reading readiness of preschoolers from an impoverished neighborhood (n = 20) was measured using a standardized test. Nationally, the mean on this test for preschoolers is 30.9, with SD = 2.08.

a. Children below the 30^{th} percentile (in the bottom 30%) are in need of special assistance prior to attending school. What raw score marks the cut-off score for these children?

Z-score =-2.75X = 30.9 + 2.08 (-2.75) = 25.18

Cut Off is 25.18

b. What percentage of children score between 25 and 28.5?

Z= (25-30.9) /2.08= -2.83 Z= (28.5-30.9) /2.08= -1.15

-2.83+-1.15=-3.98 50-3.98=46.02

46.02% score between 25 and 28.5

c. How many children would we expect to find with scores between 28 and 31.5?

Z= (28-30.9) /2.08= -1.39 Z= (31.5-30.9) /2.08= .28

-1.39+. 28= -1.11 Z-score= 2.29

X= 30.9 + 2.08 (2.29) = 35.66

36 Children have scores between 28 and 31.5

d. Children in the top 25% are considered accelerated readers and qualify for different placement in school. What raw score would mark the cutoff for such placement?

Z-score= 2.81X= 30.9 + 2.08(2.81) = 9.74

Cut-Off is 9.74

2. Age at onset of dementia was determined for a sample of adults between the ages of 60 and 75. For 15 subjects, the results were ΣX = 1008, and Σ (X-M)^{2} = 140.4. Use this information to answer the following:

a. What is the mean and SD for this data

M = 1008 /15 M = 67.2 SD= 140.4

b. Based on the data you have and the Normal Curve Tables, what percentage of people might start to show signs of dementia at or before age 62?

(62-67.2)

0.037

c. If we consider the normal range of onset in this population to be +/-1

Z-score from the mean, what two ages correspond to this?

d. A neuropsychologist is interested only in studying the most deviant portion of this population, that is, those individuals who fall within the top 10% and the bottom 10% of the distribution. She must determine the ages that mark these boundaries. What are these ages?

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. Age at onset of dementia was determined for a sample of adults between the ages of 60 and 75. For 15 subjects, the results were ΣX = 1008, and Σ (X-M)

^{2}= 140.4. Use this …