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Submitted by Clay1203 on Sun, 2012-05-06 01:31
due on Thu, 2012-05-10 01:30
answered 1 time(s)
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Evaluate 5.2 Problem 11

Jim Outfitters, Inc. makes custom fancy shirts for cowboys. The shirts could be flawed in various ways, including flaws in the weave or color of the fabric, loose buttons or decorations, wrong dimensions, and uneven stitches. Jim randomly examined 10 shirts, with the following results which are in the attached table.

a. Assuming that 10 observations are adequate for these purposes, determine the three sigma control limits for defects per shirt.

b. Suppose that the next shirt has 13 flaws. What can you say about the process now?

Submitted by shahimermaid on Sun, 2012-05-06 02:41
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the answer is in attached file

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file1.2_problem_11_data_set.xlsx preview (78 words)


xxxxx Defectsxxxx bar xxxxx xxxxxx xxxxx Defectsxxxx bar(xi-x xxxxxx
xx 2 xx81.36000000000000031.85
x xxx xx x0xxxxx44.09
xx xxx 7 0.36000000000000032xxxx
412x 36xxxxxxx28.73
5 xx 1x-1.6399999999999997 xxxx
6104xx x103.360000000000000311.29
x2xx 16x xxxxxxxxxxxxxxxxxxxx21.53
8 4xx 4 x4 xxxxxxxxxxxxxxxxxxx6.97
96 x x96-0.63999999999999968xxxx
xx x 0x xxx xxxxxxxxxxxxxxxxxxxxxxxx
60xxx xxxx xxxx 40.45
xx xxxxxx
xxxxx 60/10 x 6mean= 73/11= xxxx
sd= xx xx xxxxxx 3.56sd= sq rt 158.55/10=3.98
3 -sigma limits xxx means xx xxxxxx xx xxx 3 xxxxxx limits xxx xxxxx of sample of xxx
UCL x mean x xxxxxxxxxxx6 x 3(3.56/3.16) xxxxx x defects xxx = xxxx x 3(SD/Sqrtn) xxxx xxxxxxxxxxxxxx 6.64 + 3.6 x10 xxxxxxx
central line = mean 6central xxxx = mean xxxxx 7 defects
LCL=mean -3(SD/Sqrtn) xxx =3 xxxxxxx xxxxxxxx -3(SD/Sqrtn)6.64-3.6=x xxxxxxx



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