Boolean w6

 

using Relational and Logical Operators to Evaluate Logical (Boolean) Expression

Evaluate the logical (Boolean) expressions in the following exercises and circle the correct answer after you evaluation. For char and String types, use the Unicode collating sequence.

Expression

Result (Circle correct answer)

1.      int num1 = 3,  num2 = 2;

(num1  >  num2)

T          F                                                                        

2.    double hours = 12.8;

(hours  >  40.2)

T          F

3.    int  funny =  7;

(funny  !  =  1)

T          F

4.    char  letter  =  ‘ A ‘;

(‘a’ < letter )

T          F

5.    int  count =  1;

count  < = 4;

T          F

6.    double  y =  -2 . 3;

y  > =  0.0;

T          F

 

Expressions Use the following values:

X = false,  y = false,  z = true

Result

(Circle all possible answers)

1.    !  (  x | | y)  | |  z

T     F     short - circuit

2.    x  &&  z  &&  y

T     F     short - circuit

3.    !  x   |  |  (y   |  |  !  z)  

T     F     short - circuit

4.    x   | |   (z   &&  (y   | |   x)  )

T     F     short - circuit

5.    true  | |  !  z  &&  y

T     F     short - circuit

6.    !  (x  | |  y)  | |  x

T     F     short - circuit

7.    z   &&   x   &&   y

T     F     short - circuit

8.    !   x   | |   (y   | |   !   z)

T     F     short - circuit

9.    x   | |   (y   &&   (x   | |   z)  )

T     F     short circuit

10.    false   | |   !   x   &&   y

T     F     short - circuit

 

 

 

 

Expression Use the  following values:

X = false,  y = false,  z = true

T     F    

(Circle all possible answers)

 

Result

(Circle all possible answers)

1.    String  name1 = “Aaron” ;

String  name2 = “aaron” ;

name1. compareTo(name2)= = 0

T     F 

2.    String name1 = “Aaron” ;

String name2 = “Aardvark” ;

namel. compareTo(name2) > 0

T          F

3.    Boolean flag = true;

int a = 2,  b = 5,  c = 10;

(a  *  b  <  =  c  &&  !  flag)

T          F

4.    String  name1  =  “Aaron” ;

String  word  =  “A” ;

name1 .compareTo(word)  <  0

T          F

5.    int  x = 2;

double   y   =   1 . 1;

(x  -  y)  = =  0 . 9

 

T          F

 

 

 

 

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