# 37 algebra questions

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## Solutions

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xxxx xxxx for xxxxxx 3:

x xx the xxxxx xx the xxxx xxxxxxxxxxx xxxx equation y = mx x xx x xxxxxxx the mileage, so x must be a xxxxxx xxxx xxxxx xxx the xxxx xxxxxxx xx relation to mileage. And it xx xxx price per xxxx xxx xxxxxxxxx xxx xxx maintenance:

m x 0.48

b xxxxx’x xxxxxx xx xx and xx is there, whether x = x or something xxxxx xxx that xx xxx xxxxx cost xx owning xxx car for one month xxxxxxx xxxxxxx xxxx =150.10

C. xxx fixed xxxx of owning the xxx for one xxxxx xxxxxxx xxxxxxx it

A

xxx xxxxxxxxxx xxxxxxxxxx is

Show xxxx xxx number xx

xx have xx xxxxx xx xxx xx In xxxx xxxxx xx xxx reverse the xxxx and the right side of xxxxxxxxx

Now xxxxxx xxx xxxxx equation xxxx xx

The xxx term xxxxxxx out and we divide again with H:

xxx H/H term xxxxxxx out, and on xxx xxxxx xxxx xx xxxx xx solve xxx double fraction:

xxxx xxxx xxx number xxx

xx x xx variable (time xx years), xxxx the xxxxxxxx that calculates the xxxxxx in xxxxx of rain xxxxxx is xxxxxxx It

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C

C The x-value when y=3 xx xx -2

xxxx xxxx for number xxx

xx order to solve this xxxxxx of equations with substitution, xx xxx xxxxxxx x from xxx first equation in xxxxx of xx xxx substitute xxxx xxxxx in xxx second equation, but xxxx xx xx careful xx have xxxxxxxxxxxx

Now we xxxxxx xx to get xx

So the solution xx (5, xxx

Show work xxx xxxxxx 17:

xx xxx xxxx xxx speed of xxx xxxxxxx xxxx xxx the xxxxx of the current with . When the tugboat xxxx upstream, the total xxxxx of xxx tugboat xx , since xxx current xxxxx it down. We xxxx xxxx xx xxxxx 140 xxxxx in xx hours and since xxx formula for speed (velocity) xx x we xxx write:

and xxxxxxx xxx the downstream xxxx (total xxxxx xx now xxx xxxxx

Now we have xxxxxx xx two equations, xx can xxxxx xx xx substitution, from the xxxxxx

and now into xxxxxxx

So, xxx xxxxx of the tugboat is 15 mph, xxx the xxxxx of xxx xxxxxxx xx x xxxx

Show work for number xxx

We have two points: xxxxx -12) and B(-5, -15). We can

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xxx

xx

R:

xxxx work xxx xxx

The equation that xxxxxx xxx number xx gallons xx xxxxxxxx xx time xxxxxx can be xxxxxxx as linear xxxxxxxxx

xx xxxx case, x xx xxxxxxx value xx xxx barrel and xx xx xxxx The xxxxx of a is xxx slope and it says xxx g xxxxxxx in xxxx (minutes). Since water xx drained xxxxxxxxxxxxxx at rate xx gallons xxx minute, x xx xxxx

So xx can write equation xxx

**x = xxxx t), xxx q), (c, p), xxx xxxxxxxx domain xx xxx b, c, xxxxxxx range is xxx xx p}.**

**xxxxxxx (0, xxx xxx 5.5)**

**46
(note: it xxxxx be xxxx 45, xxxxxxxxx xx xxx rounding system, xxx xx xxxxxx xx xxxx xxxxxxx**

**xxxxxx for xxxx 1: (0, 0), (1, xx**

**Points for line xx xxx 7), (2, xx**

**xxx 4)**

xxxx work xxx number xxx

In order xx xxxxxxxxx the xxxx xxx in which xxxxx xxxx xxx million inmates, xx will plug xxx in N xxx solve equation xxx x:

It was xx year xxxxx

**xxxx work for xxxxxx xxx**

xx the xxxxxxx xxxxxx xxx worth xxx $370,000 and xxxxx was about xxxxxxxxx then the total family xxx worth xx country is:

**xxxxxxx xxx xxx xxx xx**

file4.docx preview (58 words)

xx x

C. xxxxx are xx xxxxxxxxx

500

1300

xxxx xxxx xxx 39:

To solve with elimination method, xx must xxxxx xxxxxxxx one equation xxxx xx so xxxx x xxxxx cancel xxxx

xxx we xxx these two equations together:

Now xx xxxxxx it xx any of the xxxxxxxxxx xxx’s say the xxxxx xxxx

xx the xxxxxxxx xx xxxxxxx pair xxxx 2).

file5.docx preview (156 words)

xxxxxxx (0, xxxx (4, 0)

xxxx work xxx number 43:

xx we xxxx xxx xxxxxxx A(1980, xxxxxx xxx B(2000, 40000), we can xxxx xxx xxxxx of xxx line passing through those two points:

xxx we xxxx xxxxxxxxxx xxxxx xxxxxxx

xxx xxxxx tells us xxx the xxxxxx xxxxxxx xxxx xxx number xx xxxxxx We xxx xxxx xxx xxxxx is positive, so:

The xxxxxx xxxxxx xxxxxx xx xxxxxxxxxx at the rate xx $1100 per year.

If xxx statement from xxx is xxxxx xx can xxxxxxxxx the xxxxxx family income xx xxxx xx xxxxxx xxx median xxxxxx xxxxxx in 2000 and xxx xxxx it xxx changed in x xxxxxx

In x years xx xxx changed xxx or x * xxxxx x $4400, xx xxx median xxxxxx income xx 2004 is:

xxxx work xxx xxxxxx 45:

If xx xxxx the xxxx of the xxxxxxxx xxxx x and xxx height xxxx h, we xxxxx

(b xxxx be converted to xxxxxxxx xxxxxxxxxx

xx xxx xxx area xxx

xx the area is yd2.

xxxxx | x |

0 | -6 |

xx | xx |

x | x |

points: (0, -6), xxx 0)

xx

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