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Question
Submitted by michiermartins on Wed, 2012-02-22 17:41
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which of the following compounds contains the largest number of atoms? 1.0 mol of CH3COCl, 2.0 mol of H2SO4, 3.0...

which of the following compounds contains the largest number of atoms? 1.0 mol of CH3COCl, 2.0 mol of H2SO4, 3.0 mol of NH3, 4.0 mol of K2S, or 5.0 mol of HBr

Answer
Submitted by Coloratus on Wed, 2012-02-22 21:00
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Complete answer with full step-by-step explanations

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We xxxx xx through each xxxxxxxx xxx calculate the xxxxxx of moles of xxxxx for xxxx xxxxxxxxx xxx xxxxxxxx xxxx the xxxxxxx number xx moles xx atoms is the xxxxxxxx xxxx the xxxxxxx xxxxxx xx atoms:

xx 1.0 mol of CH3COCl x CH3COCl has x xxxxx xx one molecule, xx the number of moles of xxxxx xxx 1.0 mol * 7 x x xxx

xx 2.0 xxx of xxxxx - H2SO4 xxx 7 xxxxx in xxx xxxxxxxxx so xxx number of xxxxx xx atoms is: xxx xxx * 7 x 14 mol

xx 3.0 xxx xx xxx x xxx xxx x atoms xx xxx molecule, xx the xxxxxx of moles xx atoms xxx 3.0 mol x x = xx xxx

d) 4.0 mol xx xxx - K2S has x atoms xx xxx molecule, xx the number of xxxxx of atoms xxx xxx xxx x 3 x 12 mol

d) 5.0 mol of xxx - HBr has 2 xxxxx xx one xxxxxxxxx xx xxx number of xxxxx xx xxxxx xxx 5.0 xxx x 2 x 10 mol

So, the compound xxxx xxx largest xxxxxx of xxxxx is xxxxxx


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Answer
Submitted by Andrein on Wed, 2012-02-22 19:28
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The answer is: 2 mol of H2SO4 (Detailed answer below)

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To xxxxxx this question xx will xxx the Avogadro's xxxxxx NA x xxxxx * xxxxx mol*(-1) .

Avogadro's number xxxxx xxxx xxxxx xxx 6.022 * 10^23 entities xxxxxxxxxxx atoms etc.) for each mol xx any xxxxx xxxxxxxxxx

For example, x mol of xx xxxx xxxxxxx 6.022 x xxxxx xxxxxx xxxxxx where as x mol xx xxx xxxx xxxx 6.022 x 10^23 xxxxxxxxx xx water, and since it xxx x atoms xx xxxx have 3 * xxxxx * 10^23 xxxxxx

x

Back to our xxxxxxxx We xxxx calculate xxx xxxxxx xx xxxxx xxx xxxx substance using xxx xxxxxxxx above.

.

.

1.0 mol of xxxxxxx has 6.022 x xxxxx molecules xx xxxxxxxx

Each xxxxxxxx xxx x atoms xx Carbon atoms, 3 Hydrogen xxxxxx one xxxxxx atom and xxx xxxxxxxx atom).

So, in xxxxx we have:

xxx mol xx xxxxxxx has 7 x xxxxx * xxxxx atoms = xxxxxx x xxxxx xxxxxx

.

.

2.0 mol of xxxxx have x x xxxxx x xxxxx xxxxxxxxx of H2SO4

Each molecule xxx 7 atoms, so xx xxxxx xx have:

2.0 mol of H2SO4 xxxx 7 * 2 x 6.022 * 10^23 xxxxx = xxxxxx * 10^23 atoms.

x

.

xxx mol of xxx have x x 6.022 x 10^23 xxxxxxxxx = 18.066 x 10^23 molecules

xxxx molecule xxx 4 xxxxxx xxx in total we have:

xxx mol xx NH3 have 4 * xxxxxx x xxxxx x xxxxxx * 10^23 atoms.

x

.

4.0 xxx xx xxx xxxx 4 * 6.022 x 10^23 xxxxxxxxx = 24.088 x xxxxx molecules

Each xxxxxxxx xxx 3 atoms, so, in total xx have:

4.0 mol of K2S have x * xxxxxx * xxxxx xxxxx = 72.264 x 10^23 xxxxxx

x

x

5.0 mol of xxx have x * 6.022 x xxxxx xxxxxxxxx x xxxxx * xxxxx xxxxxxxxx

Each molecule has x atoms, xxx xx total we xxxxx

xxx xxx xx xxx have x x 30.11

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