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Submitted by Jdpt3 on Fri, 2012-06-15 23:14
due on Fri, 2012-06-15 22:39
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Statistics Assignment

6. A population consists of the following five values: 2,2,4,4 and 8.

A. List all samples of size 2 and compute the mean of each sample.

B. compute the mean of distribution of sample means and the population mean. Compare the two values.

C. Compare the dispersion in the population with that of the sample means.

10. There are five sales associates at mid-motors ford. The five representatives and the number of cars they sold last week are:

Sales. Cars Sold

Representative.

Peter Staller. 8

Connie Stallter. 6

Juan Lopez. 4

Ted Barnes. 10

Peggy Chu 6

A. How many different samples of size 2 are possible?

B. List all possible samples of size 2, and compute the mean of each sample

C. Compare the mean of the sampling distribution of sample means with that of the population

D. On a chart compare the dispersion in sample means with that of the population.

12. Scrapper elevator company has 20 sales representatives who sell its product through out the US and Canada. The number of units sold last month by each representative is listed below. Assume these sales figures to be population values.

2 3 2 3 3 4 2 4 3 2 2 7 3 4 5 3 3 3 3 5

A. Draw a graph showing the population distribution

B. compute the mean of the population

C. Select five random samples of 5 each. Compute the mean of each sample. Use the methods described the methods to be used in order to determine the items to be included in the sample.

D. Compare the mean of the sampling distribution of the sample means to the population mean. Would you expect the two values to be about the same?

E. draw a histogram of the sample means. Do you notice the difference in the shape of the distribution of sample means compared to the shape of the population distribution?

16. A normal population has a mean of 75 and a standard deviation of 5. You select a sample of 40. Compute the probability the sample mean is:

A. Less than 74

B. between 74 and 76

C. Between 76 and 77

D. Greater than 77

18. According to an IRS study it takes a mean of 330 minutes for taxpayers to prepare, copy, and electronically file a 1040 tax form. This distribution of times follows the normal distribution and the standard deviation is 80 minutes. A customer watchdog agency selects a random sample of 40 tax payers.

A. What is the standard error of the mean in this example?

B. what is the likelihood that sample mean is greater than 320 minutes?

C. What is the likelihood the sample mean is between 320 and 350 minutes?

D. What is the likelihood the sample mean is greater than 350 minutes?

Answer
Submitted by StatSolver on Sat, 2012-06-16 02:44
teacher rated 56 times
5
purchased one time
price: $50.00

Please see the attachment for solution.

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xxxxxx see xxx xxxxxxxxxx xxx solution. xx xxx need xxx xxxxxxxxxxxxx please xxx me. xxxxxxx

xxxxxx The normal probability P(Z < z) can be calculated using the Excel formula
xxxxxxxxxxxxx xxx the xxxxx xxxx xxx computation]

file1.doc preview (1661 words)

xx A xxxxxxxxxx consists xx the xxxxxxxxx xxxx xxxxxxx 2,2,4,4 and xxxxxxx List all samples of xxxx 2 xxx xxxxxxx the mean xx xxxx sample.�B. xxxxxxx xxx mean xx xxxxxxxxxxxx of xxxxxx xxxxx and the xxxxxxxxxx mean. Compare the two values.�C. xxxxxxx xxx dispersion xx xxx xxxxxxxxxx xxxx that of xxx xxxxxx xxxxxxx

xxxxxxxxx

xx

xxxxxxxxxxxxxxxxxxxxx

Sample

xxxxxx

Mean

x

2

x

2

x

2

x

x

x

x

4

x

4

2

x

x

x

x

x

x

6

x

x

3

x

x

x

x

8

x

x

4

9

4

x

6

xx

4

x

6

xx xxx population xxxxx

x xxx x x x x + x + xxxx x xxxx = x

xxx xxxx of xxxxxxxxxxxx xx sample means,

x (2 x x x x + x x x + x + x x 4 + 6 + xxxxx = xxxxx = xx

xxxxx xxx xxxx of distribution of sample xxxxx xxx the population mean are xxxxxxx

xx The xxxxxxxxxx for xxx population xx xxxxxxx

- - - more text follows - - -


file2.xls preview (174 words)

xxxx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Sample Values xxxxxxxxxx xxxx sold xxxxxxxx sold xx xx xxxxx xx of xxxxx
x2 x 2186x4 x0
xx4x x xx 65 x x
x2x3x xxxxx x2
x 28x 486 xx0x
x xx 3x6x58 1 2
62 x3 x6108 x0 1
7 2 x x7 x 6 6xx1x
xx44 x x xx x
9xx 6 xxx5
10 x8x10xxx x

6,10

x
Cars sold
xxxxxx of Sales
xxxxxxxxxx xxxx

12

x
xxxx sold
Number of Means
xxxxxx mean

xxxxx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
DataUnits soldxxxxxxxxx xxxxxxxxxxxx Valuesxxxx
2x 0 x 3 x 2xx 2.8
3 2x 2 2 x x x x 3.2
2 3x3x4 3 x 5 3.4
34xx4 x73 xxxx
xx2x 2 x x 43 xxx
x 6 x
2 7 x
4
x
2
x Sample xxxx Frequency
x 2.8 x
x3.2x
4xxx x
x3.8 1
x
3
x
x
x

xxxxx

xxx
0
5
9
x
x
0
1
xxxxx xxxx
Frequency
xx
x
2
1
1
xxxxxx xxxxx
xxxxxxxxx
xxxxxxxxxxxxxxxxxx
Question 16Question 18
xx xxx < z)x xP(Z < xx
xx -1.26490.1030xxx -0.7906xxxxxx
76xxxxxx xxxxxx 350xxxxxx 0.9431
xx2.5298 xxxxxx


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Answer
Submitted by Kumail Raza on Sat, 2012-06-16 07:02
teacher rated 23 times
4.52174
price: $50.00

Answer file is attached with all calculations and with easy printing format. Feel free to contact for any further assistance

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file1.xlsx preview (1405 words)

xx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
xxxxx
Population xxxx x x2 , x x4,x
Required:
A. List all samples of xxxx x and xxxxxxx the xxxx xx xxxx sample.
B. compute xxx mean xx xxxxxxxxxxxx xx xxxxxx means and the xxxxxxxxxx mean. xxxxxxx the xxx xxxxxxx
Solution:
No. xx Possible xxxxxxx C nxxx x (For without replacement
=10
xxxxxx No. xxx xxxxxxxx xxxxxxxSample xxxx (x)
1x , xx
x 2, x3
xx x4x
42 x 8 5
52 , x 3
x xx 43
Sample xxx7x, x5
x4 , x 4
94, 8 6
10x, x x
Total xx
xxxxxx distribution of x xx xfxx
xx x
3 4 12
x 1x
x x xx
x 212
Total 1040
xxxxxx mean = x
Population mean x x 2xxx4x x+8 ) / x
4
Population means xxx sample means xxx xxxxx
xx xxxxxxx the xxxxxxxxxx in the xxxxxxxxxx xxxx that of xxx xxxxxx means.
x8 xx
Range of

- - - more text follows - - -



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Answer
Submitted by shahimermaid on Sat, 2012-06-16 10:34
teacher rated 376 times
4.353725
price: $30.00

the answer is attached

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file1.docx preview (946 words)

6. x population xxxxxxxx of the xxxxxxxxx five xxxxxxx 2,2,4,4 xxx 8. A. xxxx all samples xx xxxx x and xxxxxxx xxx mean xx xxxx xxxxxxx

xxxxxxx xx size 2 are

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

xxxx

xxxxxxxxxx from xxxx xxx

Square xx difference

2,2

2

xx

4

2,4

3

-1

1

2,4

3

-1

x

xxx

x

x

1

2,2

2

xx

x

xxx

3

xx

x

2,4

x

-1

1

xxx

5

1

x

xxx

3

xx

x

xxx

x

-1

x

4,4

4

x

0

4,8

6

2

x

4,2

3

xx

1

xxx

x

-1

1

4,4

4

x

x

4,8

x

x

x

8,2

x

1

1

8,2

x

1

1

xxx

x

2

x

8,4

6

x

x

xx xxxxxxxx xxx xxxx xx xxxxxxxxxxxx of sample means xxx xxx xxxxxxxxxx xxxxx xxxxxxx xxx two xxxxxxx

Mean xx xxxxxxxxxxxx of sample means xx called xxxxxxxx xxxxx of X. it is xxxxx xx the xxxxxx

∑sample mean= xxxxx xx

Population mean xx xxxxxxxxxx

- - - more text follows - - -



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Answer
Submitted by shahimermaid on Sat, 2012-06-16 10:34
teacher rated 376 times
4.353725
price: $30.00

the answer is attached

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file1.docx preview (979 words)

xx A population consists xx the following five xxxxxxx xxxxxxx xxx 8. A. List xxx xxxxxxx of size 2 xxx compute the xxxx of each xxxxxxx

xxxxxxx xx size 2 are

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx

mean

Difference xxxx mean xxx

xxxxxx of xxxxxxxxxx

xxx

2

xx

4

xxx

x

-1

x

xxx

x

-1

1

2,8

5

x

x

xxx

x

-2

4

xxx

3

-1

x

2,4

x

-1

x

2,8

5

x

1

xxx

3

xx

x

4,2

3

-1

x

xxx

4

x

x

xxx

6

2

4

4,2

3

-1

x

xxx

3

-1

x

xxx

x

x

x

xxx

x

x

4

xxx

5

1

1

8,2

x

x

x

xxx

6

x

x

8,4

6

2

4

B. xxxxxxxx xxx xxxx xx distribution of sample means xxx xxx xxxxxxxxxx mean. Compare xxx two xxxxxxx

Mean xx distribution of xxxxxx xxxxx is called expected value xx xx xx is xxxxx in the xxxxxx

∑xxxxxx mean= xxxxx =4

xxxxxxxxxx mean xx 2+2+4+4+8=

- - - more text follows - - -



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