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Question
Submitted by mellyfelly29 on Mon, 2012-04-23 11:05
due on Fri, 2012-04-27 11:01
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statistics
4

Statistics

Answer
Submitted by rajendrabnk on Wed, 2012-04-25 02:33
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please find it attached

body preview (5 words)

xxx the parts are done.

file1.xls preview (98 words)

xxxxxx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
DataPART A
7.7
6.3Σxi 219.6
7.9xxxxxx xx data xxxxxx 27
7.2
9.7 mean xxxxx xx xxxxxxxx for xxx xxxxxxxxxx xxxxxxxxxx 8.1333333333
7.7
xxxxPART B
xxx
xxx A xxxxx xxxxxxxx xx the strength xxxxx xxxx xxxxxxxxx xxx weakest 50% of all such beams from the xxxxxxxxx 50% xx xxxxxx a MEDIAN.
8.7
7.8 Median7.7
6.8
6.3
xxxPART C
7
11.8xxxxxxxx xxxxxxxxx xx xxxxxx xxxx of xxxx xxxxxxx xx xxx squares less xxx square xx xxx xxxxxxxx
xxxx
6 Σxi2xxxxxxx
xxx Average of xxxxxxx xxxxxxxxxxxxx
xxxxxxxxx of xxxxxxx 66.1511111111
xxx
11.6 xxxxxxxx xxxxxxxxxxxxxxxxxxxxx
xxx
7xxxx D
xxx
9xxxxxx of xxxxxx xxxxxxx xxxx 10 4
xxx Total number 27
Proportion0.1481481481 xxxxx
xxxx x
Standard deviation xxxx 1.6311777159
mean value of strength for the conceptual population(μ)xxxxxxxxxxxx
xxxxxxxxxxx of variation xxxxx xxxxxxxxxxxx

xxxxxx

x

xxxxxx

x

file2.xls preview (103 words)

xxxxxx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
xxxxPART A
7.7
6.3Σxi xxxxx
xxx xxxxxx xx data xxxxxxxx
xxx
xxx mean value of xxxxxxxx for xxx xxxxxxxxxx population8.1333333333
xxx
10.7PART x
8.1
7.3A point estimate xx the xxxxxxxx value that separates xxx xxxxxxx 50% xx xxx xxxx beams from xxx xxxxxxxxx xxx xx xxxxxx x xxxxxxx
xxx
xxxMedianxxx
xxx
6.3
6.8 xxxx x
x
xxxx Standard xxxxxxxxx is sqaure root xx xxxx average xx xxx xxxxxxx xxxx xxx square xx the average)
11.3
x Σxi2 xxxxxxx
xxxxxxxxxx of squares 68.8118518519
7.4Square of xxxxxxx66.1511111111
8.1
11.6Standard xxxxxxxxx1.6311777159
6.5xxxxxxxx deviation xxx xxxxxxx method) xxxxxxxxxxxx
7xxxx x
7.1
9 xxxxxx of values greater xxxx 10 x
xxx Total xxxxxxxx
xxxxxxxxxxxxxxxxxxxxxx orxxx
xxxx E
xxxxxxxx xxxxxxxxx xxxxxxxxxxxxxxxx
xxxx xxxxx xx xxxxxxxx for xxx xxxxxxxxxx population(μ)xxxxxxxxxxxx
xxxxxxxxxxx of variation xxxxx 0.2043750688

xxxxxx

Sheet3

x


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