A researcher predicts that watching a film on institutionalization

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#1 A researcher predicts that watching a film on institutionalization will change

students’ attitudes about chronically mentally ill patients. The researcher

randomly selects a class of 36 students, shows them the film, and gives them

a questionnaire about
their attitudes. The mean score on the questionnaire for these 36 students is

70. The score for a similar class of students who did not see the film is 75.

The standard deviation is 12. Using the five steps of hypothesis testing and

the 5% significance level
(i.e. alpha = .05), does showing the film change students’ attitudes towards the

chronically mentally ill? 1. What does it mean to set alpha at .05? 2. What is

your null hypothesis? Alternate hypothesis? 3. Is this a one-tailed or two-tailed

hypothesis? 4.
What is the critical z? 5. Suppose the obtained z was -2.5. Do you reject or fail

to reject the null hypothesis? 6. State in words what you have found #2 Using

the ANOVA source table below. The table depicts a two-way ANOVA in which

gender has two groups (male
and female), marital status has three groups (married, single never married,

divorced), and the means refer to happiness scores (n = 100): a. What is/are

the independent variable(s)? What is/are the dependent variable(s)? b. What

would be an appropriate null
hypothesis? Alternate hypothesis? c. What are the degrees of freedom for 1)

gender, 2) marital status, 3) interaction between gender and marital status, and

4) error or within variance? d. Calculate the mean square for 1) gender, 2)

marital status, 3) interaction
between gender and marital status, and 4) error or within variance. e. Calculate

the F ratio for 1) gender, 2) marital status, and 3) interaction between gender

and marital status. f. Identify the critical Fs at alpha = .05 for 1) gender, 2)

marital status,
and 3) interaction between gender and marital status. g. If alpha is set at .05,

what conclusions can you make? Source Sum of Squares (degrees of freedom

[df]) Mean Square Fobt. Fcrit. Gender 68.15 ? ? ? ? Marital Status 127.37 ? ? ?

?

Gender * Marital Status
(A x B) 41.90 ? ? ? ? Error (Within) 864.82 ? ? NA NA Total 1102.24 99 NA NA

NA Please Note: The table that you see has been slightly modified from the one

presented in the module notes since it is beyond the scope of this unit to have

students calculate p
values. Instead you are asked to calculate the F value and compare it to the

critical F value to determine whether the test is significant or not

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