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ch-19, online questions
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Ch 7 & 8
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07.HE.A: Measurements were made of xxxxxxxxxxx xxxxxx xxx packed cell volume 5of 21 patients xxxx xx xx xx xxxxx data are xx CE6. 6
a. Make a xxxxxxxxxxx of xxx xxxxx considering PCV as xxx xxxxxxxxxxx xxxxxxxx and Hb as xxx dependent variable.
xxxxxxx xxxx xx the best xxx to start xxxxxxxxx xxxx xxxxxxxxxxxx xxxxxxx 2 quantitative variables. xxxxxxxxx looks like xx xxxxxx plot xxxxx that as xxx xxxxxxxxxx xx xxxx increases. xxxx is x xxxx of positive xxxxxxxx xxxxxxx PCV and Hb. The form of xxxxxxxxxxxx looks like x linear relation. The next xxxxxx xx xxx xxxxxx xxx relationship looks. From xxxx diagram x the relationship xxxxx xxx too xxxxxx xxx certainly, xx xx not xxxxx
xx Calculate xxx correlation xxxxxxxxxxx between PCV xxx xxx
Simple xxxxxx xxxxxxxxxx xxxxxxxx
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ch -19, 3 questions
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In xxxxx a xxx xxxxx xxxxxxxxxxxx xxxxxx reported xx xxxx xxxxx xx 207 women xxxxx xxx age of 40 who had xxxxxxxxxx xxxx xxxxxx to conceive.
Find 90% xxxxxxxxxx interval xxx xxx success rate at this xxxxxx
Interpret your xxxxxxxx in xxxx context
Explain xxxx 90% confidence xxxxx
xx xxxxx data refute xxx clinic’x xxxxx xx a 25% success xxxxx Explain.
A
xx have
x x 49/207 = xxxx zc = 1.645 xxx x = 207
We xxxxxxxxxx
xxxx xxx 1.645 xx rt( 0.24 x 0.76)/207 =
xxxx xxxxxxxx x 0.03= xxxx + xxxxx and 0.24 xxxxxx
0.191 and 0.289
xx xx xxx 90% confident, xxxxx on this xxxxxxx xxxx xxx xxxxxxxxxx xx all women who were previously xxxxxx xx xxxxxxxx xxxx xxxxxxx a xxxxxxx xxxx at this xxxxxx between xxxxx and xxxxxx
c) xx we xxxx xx select xxxxxxxx
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ch-18, 2 questions
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x
P= xxxx
N=732
xxxx x 0.04
xx x sq rt xxxxxxxxxxxx
1) sample xx random
xx 10% condition x number xx successes = 732 x 0.04 =29 and xxx xx xxxxxxxx =0.96 x 732 = 702
My xxxxx for p is xxxxxxx xxxxxxx
Probabilty xxxx in xxx xxxxxxx 20 are having the xxxx
Probability = 20/732 x xxxx
For xxx between 18 xxx xx years, xxxxx cholesterol levels xxx mg/100mL) xxxx x mean of xxxxx xxx x xxxxxxxx deviation xx 40.7 xxxxxx xx xxxx from the National xxxxxx xxxxxxxx
Mean = 178.1
xxx 40.7
xxxx xxx xxxxxxxxxx of males aged 23, who have a xxxxx cholesterol level of 210mg/100mL xxx xxxxxxx Is this xxxxx unusually high?
x =( 210-178.1)/40.7 x xxxxx
P(z x 0.784) =0.7823
x >= 0.784 xxxx xx x – 0.7823 x xxxxxx
xxx xxxxxxxxxx of xxxxx xxxxx 210mg/100ml will xx 21.77%
In a xxxxx xx 25 xxxxx xxxx xxx xxxx is xxx xxxxxxxxxxx xxxx the mean xxxxx cholesterol xxxxx xxxxxxxxxxxxx (or xxxxxxx Is xxxx level xxxxxxxxx xxxxx
Probability xxxx xxxx xxxxx cholesterol level is210mg/100mL xx above = xxxxxx
xxxxxxx the assumptions xxx xxxxxxxxxx that xxxxxxx your model, and draw a xxxxxxxx xxxxxxx xxxxxxxx
1) sample is xxxxxx
2) 10% condition = number xx xxxxxxxxx and no. xx xxxxxxxx are more xxxx 10
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ch 5 & 6
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In the xxxxx xxxxx is xxx with xxxxxxxxx multimedia assistant, xxx z = xxxxx and find the xxxx
I xxxx mentioned xxxx xxxx xx Q6 a, xxx can xxxx this in xxxx of your book xxx xxxx xxx xxx x have used the xxxxx xxx find xxx %age.
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ch-17 2 questions
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xx xxxx ) Probability that the citizen xxxxx their dentist xxxxx x year=p= xxxxxx
xx xxxxxxx trial n= xx
Exactly 6 xxxxxxxxx xx x trial of xx means, 6 xxxxxxxxx and x failure
10C6 = (10)!/(6)!(10-6)!=10.9.8.7.6!/6! x 4.3.2.1=210
Probability xxxx xxxxxxx xxx see xxxxx dentist twice a year x 210 x (0.60)6 x (0.40)4
x 210 x xxxxxxxx x xxxxxx x 0.25 x xxx
At xxxxx six means P(6)+P(7)+P(8)+P(9)+P(10)
using statcrunch, xx>6, xxxxx
For xx xxxx xx using xxxxxxxxxx x<xxx 0.62
xxxxx np x 10 x xxxx x
xx = xx xx (npq) = xx xx xxx x .6 x xxxx 1.55
17 HE x
N= xxxxx xxxxxxx , xxxxxxx
xxxx = xxx xxxx x xxxx xxx
xx x sq rt(npq)= xx rt xxxxx x xxx x xxxxx xxxxx
x A normal xxxxx xx x close xxxxxx xxxxxxxxxxxxx only xxx a xxxxx number of trial
A binomial xxxxx is approximately normal,
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ch-4 2 questions
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xxxxxxxxx gives x snapshot xx the xxxxxxxxx xx xxx xxxxxxxx occurring at xxxxxxx xxxxx but the xxxx xxx xxxx display is better option xx it depicts the individual xxxxxxx
Variable: xxxx Decimal point is x xxxxxxxx xx the xxxxx xx xxx xxxxxx 2 x 8 3 : x : xxxxx x 4 : xxxxxxxx : xxxxx : xxxx : 02 6 : 6 7 x xx
Stem and leaf display organizes xxxx xxxx xxxxxx xxxxxx xxxxx xxx the values within xxxx group branches out to thr right xx each row. xxxx xxxxx xxx the data xx distributed xxx xxxxx concentration xx xxxx occurs. xx xxxx xxxxx it xx xx xxx line xx xx’s.
b) mean= xxxxx
xxxxxxx 50
c) xxxxxxxx
xxxxxxxxx xxxxxx
xxx 11.77
xxxxxxx statistics:
xxxxxxxxxxxx | xxxx | xxxxxxxx | xxxx xxxx | Median | xxxxx |
var1 | xxxxx | xxxxxxxxx | 11.771844 | 50 | 45 |
The xxxxxxx xxxxx is xxxx xxxxxxx values are xx xxx xxxx xx 40 xxx mean, xxxxxx are xxxxx xxx xxxxxx values.
Q4B
b)The xxxxx between histogram xxx xxxxxx gap xx the data, xxxxxxxxxx x xxxxxx xxxxx xxxxx xxx no xxxxxxx
xx five number
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There are 2 question of Ch-2 and 2 of Ch-3
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xxxx Q 4, Stress is a quantitative xxxxxxxx
xx B. 5W’s – Who, What, When, xxxx xxx xxx
Who- Medical researchers at x large hospital,
xxxxx Response xx xxxxxxxx xx the treatment
xxxx – xxxx xxxx to 2005
xxxxx xxxxxx patients undergoing chemotherapy
Why- x Impact of xxx type xx xxxxxxxxxxxx on four types xx blood xxxxxx
The data is categorical, as xxxxxxxxxx on xxx xxxxx of age, xxxx type xx xxxxxxx stage xxx xxxxxxx xxxxxx responded to the treatment.
xxxxxxx 3: xxxxxxxxxx and xxxxxxxxxx Categorical xxxx
HE.A
xxxxxxxHeart xxxxxxx | 27.9 |
Cancer | 22.8 |
Circulatory xxxxxxxx xxx Stroke | xxx |
Respiratory xxxxxxxx | xxx |
xxxxxxxxx | 4.5 |
xxxxx xxxxxx | xxxx |
Bar chart
xxxxxxxxx
xx HEB
Age
xxxxxxxxxxxxxxxxxxx Pressure | Under xx | xxxxx | xxxx xx | total |
Low | 27 | 37 | xx | 95 |
xxxxxx | xx | xx | 93 | xxx |
High | 23 | xx | xx | xxx |
total | xx | xxx | 197 | 474 |
Percentage xx patients over xx x 197/474*100 x xxxxx
xxxxxxxxxx of patients having High xxxxx xxxxxxxx x xxxxxxxxxxx xxxxxx
xxxxxxxxxx of
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ch 16, 2 question in attached file
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xxxxxxxx
xxxxxxxxxxxxxxxxxxxxxxxxxxxxxX | xxxx | xx P(x)=E(x) | xxxxxxxxx (x-E(x) | xxxxxxx xxxxxxxxx | xxxxxxxx | xx |
0 | 0.05 | 0 | xxxxxx | 4 | xxx | 0.45 |
1 | 0.25 | xxxx | 1-2=-1 | x | xxxx | 0.5 |
x | xxxx | xxx | 2-2=0 | x | 0 | x |
3 | 0.15 | xxxx | xxxxx | x | 0.15 | 0.39 |
4 | 0.15 | 0.6 | 4-2=2 | x | xxx | xxxx |
x | xxxx | 0.25 | 5-2 =3 | 9 | 0.45 | 0.67 |
Total x xxxxxxxxxxxxxxxxxx
Expected xxxxx xx a xxxxxx variable xx xxxxx by multiplying the value of x with xxx xxxxxxxxxxx xxxx xxx xxxxxx them.
Expected xxxxxx of patients can xx found on the table xx 3rd xxxxxxx xx xxxxxx cannot xx xx fraction, we xxxxx off.
Shown xx xxxxx
xxx ER staff xxxxxx xxxxxx x xxxxxxxx xx xx xxxxxxxx on x given xxxx
xxxxxxxx = 1.65, xxx xx rt xxxxxxxx x xxxx
Q
xxxxxxxxxxxX | xxxx | E(x) | deviation | xxxxxxx xxxxxxxxx | variance |
0 | xxxxxx | x | xxxxxxxxx -3.9598 | 15.68 | 0 |
1 | 0.0001 | 0.0001 | 1-3.9598= xxxxxxx | 8.76 | xxxxxxxx |
x | xxxxxx | xxxxxx | 2-3.9598= xxxxxxx | xxxx | xxxxxxxx |
x | xxxxxx | xxxxxx | 3-3.9598= -0.9598 | 0.92 | xxxxxxxx |
4 | xxxxxx | 3.8424 | xxxxxxxxx xxxxxx | xxxxxx | xxxxxxxx |
Total xxxxxxxxxxxxxxxxxxxxxx
Expected xxxxxx 3.9598
xx x xxx
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final submission
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x xxxx not xxxx 22 x
xxxxxxxx
(f), compute x xxx xxxxxxxxxx xxxxxxxx and xxxxxxx the xxxxxxxx xx context.
xx Control group xxxxxx was used to collect the xxxx
xxxxx
361 xxxx no xxxxxxxxxx x xx xxxxx p1= xxxxx xxx xxxx
89 xxxxxxxx xxxx xxxxx depression, 26 xxxxx xxx 0.29, xxx xxxx
b) Ho: there xx xx xxxxxxxxxxx between depression and death
H1: xxxxxx with xxxxxxxxxx xxx xxxxx
c) Assumptions xxx
Independence xxxxxxxxxxx within each xxxxxx xxx data xxxxxx xx based on xxxxxxx xxx xxxxxxxxxxx xxxxxxxxxxxx
Randomization Condition: The data in xxxx xxxxx xxxxxx xx drawn xxxxxxxxxxxxx and at random xxxx a xxxxxxxxxxx xxxxxxxxxx xx xxxxxxxxx by a randomized comparative xxxxxxxxxxx
xx the data are xxxxxxx xxxxxxx xxxxxxxxxxxx xxx sample should not xxxxxx 10% of xxx xxxxxxxxxxx
Both xxxxxx xxxxxx be big xxxxxx xxxx xx least 10 success xxx xx xxxxxxxx xxx there.
xx xxxx √xxxxxxxxx √xxxx x 0.81/361=0.0261
xxxx √p2.q2/n2= √xxxx x 0.71/89=0.0481
Standard xxxxx xx xxx xxxxxxxxxx in xxx xxxxxx
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