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Question
Submitted by Dadato on Fri, 2012-08-10 19:25
due on Sun, 2012-08-12 19:15
answered 2 time(s)
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Please due on Sunday 12, Thanks!

Answer
Submitted by StatSolver on Sun, 2012-08-12 00:24
teacher rated 56 times
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purchased one time
price: $15.00

Answer rating (rated one time)

5

Please see the attachment for solution (Second Part 1-7)

body preview (38 words)

xxxxxx see the attachment xxx solution. xx you xxxx any clarification xxxxxx message xxx xxxxxx xxxxx a 5 star xxxxxx xx you are satisfied with xx xxxxxxxxx The xxxx file xxxxxxxx the solution and xxxxx file contains the computations.

file1.doc preview (1568 words)

For the xxxx xxx xxxxx below, xx xxxx xxxxxxxxxx (a) xxxxxxx the xxxxxxxx xxxxx the xxxxx xxxxxxxx for xxx (b) xxxxxxxx the residuals are normally distributed, xxxxxxxxx Sb1. xxx Assuming xxx residuals are normally xxxxxxxxxxxx test xxxxxxxx xxxxxx xxx β1≠x xx the a=0.05 level xx significance. The null xxxxxxxxxx xx that x xxx x are not linearly xxxxxxxxx

X x x 5 7 8

Y 5 x x 13 15

Determine xxx xxxxx xxxxxxxx for xxx xx ≈ xxxxxxxxxxx not round xxxxx the xxxxx answer. xxxx xxxxx xx xxxx xxxxxxx places as xxxxxxxx

xxxxxx that b1 xx the estimate xx slope of xxx regression xxxx β1. The sample standard xxxxx xx b1 xx xxxxx xx xxx xxxxxxxxx xxxxxxxxx

In xxxxx to xxxxxxx xxx hypothesis xxxxx xxxxx calculate the xxxx xxxxxxxxx t0.(Explain the xxxxxxx xxxxxxxx xx do not xxxxxxx xx xxx relation exists xxxxxxx x and xxxxx

xxxxxxxx

xx x 0.5807

Sb1 = xxxxxx

t0 = b1/Sb1 = xxxxxxxxxxxxx x 15.0312

Since xxxx is a xxx tailed xxxx with x -2 x 5 – 2 x 3 xxxxxxx xx

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file2.xls preview (250 words)

xx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
X x xx xxxxxxxxx (Residual)^2 xxxxxxxxxx
xx xxxxxxxxxxxx0.4240 5.76
xx 6.4535xxxxxxxxxxxxxxxxx
x88.5581 xxxxxxx xxxxxx0.16
7 xxxxxxxxx xxxxxx 0.0541xxxx
8 15 14.8721 xxxxxxxxxxxxxxxx
xxx1.011617.2000
Xbar xxx
xxxxxx xx =xxxxxx
xxxxxxxxxx bo =xxxxxxx
n =x
xx xxxxxxx
Sb1xxxxxx
t x xxxxxx = xxxxxxxxxxxxx
xxxxxxx x0.0006

Q2

xxxxxxxxxxxxxxxxxxxxxxxxxx
X YY^ Residuals (Residual)^2(X-Xbar)^2
xx 98 xxxxxxxxxxxxxxxxxxxxxx xxx
xx95xxxxxxx xxxxxxxxxxxxxxx
xx91 xxxxxxx xxxxxx xxxxxxx x
xx 81 79.2000 xxxxxx xxxxxx100
xx68 xxxxxxx-3.8000xxxxxxxxxx
xxxxxxxxxxxxxxxxxxx
xxxx 40
xxxxxx xx x -0.7400
xxxxxxxxxx bo x116.2000
x x5
xx x 4.0661
Sb10.1286
x = b1/Sb1 =xxxxxxx
P-value x0.0104

xx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
X Y Y^ Residualsxxxxxxxxxxxx (X-Xbar)^2
3330 48504899.7239 xxxxxxxx2472.4674 258064
xxxx 4190 xxxxxxxxxxxxxxxxx 6589.0194 40804
33805020xxxxxxxxx 76.0119 5777.8126311364
xxxx4070 3987.882182.1179xxxxxxxxx xxxxxx
2480xxxx xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Sum xxxxxxxxxxxxxxxxxxxxx
Xbar xxxx
Slope, xx =xxxxxx
Intercept, bo = xxxxxxxxx
x xx
xx x86.2637
xxx0.0863
x x xxxxxx = 10.2609
P-value =0.0020
xxxxxxxxxx xxxxxxxx
xxxxxx x xxxxx
lower limit =0.611
xxxxx limit x xxxxx
xxxxxxxx =4607.63
xxxxxxx xxxxxx
xxxxxxxxxx Statistics
Multiple x0.9861
R Squarexxxxxx
xxxxxxxx x xxxxxx xxxxxx
Standard Error86.2637
Observationsx
xxxxx
xx xxxxx xxxxxxxxxxxx F
xxxxxxxxxx1 xxxxxxxxxxxxxxxx783475.712227913105.2856 xxxxxx
xxxxxxxx 3 22324.287772087 xxxxxxxxxxxxxxx
xxxxx x805800
Coefficients Standard Errort xxxx P-value Lower xxx xxxxx 95%Lower 95.0%Upper xxxxx
Interceptxxxxxxxxx 246.5126 7.9174 xxxxxxxxxxxxxx 2736.244 xxxxxxxxxxxxxxxx
Xxxxxxxxxxxxx 10.2609xxxxxx 0.611 1.160xxxxx 1.160
xxxxxxxxxxx OUTPUT
Percentile x
xx4070
xx4120
50 4190
xx xxxx
905020

xx

xxxxxx Percentile
Y
xxxxxx Probability Plot

Q5

x xx x xxxxxxxxx + xxxxxxxx x x 46.38

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Answer
Submitted by StatSolver on Sat, 2012-08-11 10:05
teacher rated 56 times
5
purchased one time
price: $30.00

Answer rating (rated one time)

5

Please see the attachment for solution (Question 1 - 9)

body preview (31 words)

xxxxxx see the attachment xxx xxxxxxxx of xxxxxxxxx x to xx The xxxx xxxx contains xxx xxxxxxxx and xxx Excel file contains the computations. If you xxxx any clarification xxxxxx ask xxx xxxxxxx

file1.doc preview (2604 words)

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file2.xls preview (427 words)

xx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
XY(X -Xbar)/Sx (Y -Ybar)/Sy [(X xxxxxxxxxxxxxx -Ybar)/Sy]
x 3-1.56893-0.73030 1.14578
xxxxxxxxx xxxxxxxxxxxxxxx
x6 0.00000 0.36515xxxxxxx
x 90.392231.460590.57289
9 5xxxxxxx0.00000xxxxxxx
Sumxxxxxxx
xxxx =6
Ybar x x
Sx =2.54951
Sy x2.73861
x = x
r x xxxxx

Q2

xxxxxxxxxxxxxxxxxx
x Y(X -Xbar)/Sx (Y -Ybar)/Sy xxx xxxxxxxxxxxxxx -Ybar)/Sy]
3590 xx xxxxxxx -0.97827-0.5922
269026-1.582611.46740-2
3180 xxxxxxxxxx 0.55028 xx
3565 xx 0.54455 -0.36685 xxxxxxx
3680 19 0.82413 -0.67256 -1
xxx-3.8839
Xbar xxxxx
Ybar x 21.2
Sx x411.34535
xx x3.27109
x = x
r = -0.971

Q3

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
MRI (X)xx (Y) xx -Xbar)/Sxxx xxxxxxxxxxxx xxxxxxxxxxxxxx xxxxxxxxxx
xxxxxx xxx -0.56889 -1.00000 xxxxxx
991305 1381.15466 xxxxxxx 0
856473 141xxxxxxxx1.00000 xx
xxxxxxxxxx
xxxx x901853
xxxx =138
Sx xxxxxxxxxxxx
xx x 3.00000
n = 3
r x xxxxxx
MRI xxxxx xxx(X xxxxxxxxx(Y -Ybar)/Sy [(X xxxxxxxxxxxxxx -Ybar)/Sy]
924060xxx xxxxxxxx 0.57735 -0.5172
xxxxxx xxxxxxxxxxxxxxxxxxx x
xxxxxxxxxx1.07884 0.57735 x
Sumxxxxxx
xxxx x975951
Ybar x136
xx x xxxxxxxxxxx
xx x3.46410
x xx
x x xxxxx

xx

xxxxxxxxxxxxxxxxxxxxxx
x Y(X -Xbar)/Sx(Y xxxxxxxxx[(X -Xbar)/Sx]*[(Y xxxxxxxxxx
3 x xxxxxxxx xxxxxxxx 1.0663
45-0.62385xxxxxxxx 0.4105
56-0.10398 -0.38389 0.0399
69 xxxxxxxxxxxxxx 0.1825
x xxxxxxxxx xxxxxxx2.2352
xxx xxxxxx
xxxx x xxx
xxxx xxxx
xx = 1.92354
Sy =3.64692
n =5
x =xxxxx
Slope, b1 =1.8649
xxxxxxxxxx bo = xxxxxxx

Q4

x
x
Y

Q5

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
XY(X -Xbar)/Sx xx -Ybar)/Sy xxx -Xbar)/Sx]*[(Y xxxxxxxxxx
xxxxx xxxx xxxxxxx 1.46303 xxxxxx
xxxxxxxx xxxxxxxx -1.01286 1.6160
25.5 xxxx-0.89347 xxxxxxxx0.9050
xxxx xxxxxxxxxxxx-0.18757xxxxxx
xx xxxxxxxxxxxxxxxxxxxxxxxxxx16.9
27.75xxxx xxxxxxx1.05038 1.1354
27 xxxxxxxxxxx xxxxxxxx xxxxxxx
xxxx17.50.861560.63773xxxxxx
26.75 17.3xxxxxxx-0.18757xxxxxxx
xxxxx xxxx0.20342 xxxxxxxxxxxxx
27.517.5 0.86156 xxxxxxx0.5494
Sum xxxxxx
xxxx

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