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Submitted by Dadato on Thu, 2012-08-02 15:35
due on Sat, 2012-08-04 15:32
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HWK

Please I need it by Saterday 4th. Thanks!

W

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Answer
Submitted by StatSolver on Sat, 2012-08-04 06:30
teacher rated 26 times
5
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Please see the attachment for solution (Question 11 - 13)

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xxxxxx see the xxxxxxxxxx xxx solution 11 to xxx Not that xxx critical xxxxxx xx question xx and 13 are written in two decimal places. If xxx xxx xxxxxxx xxx xxxxx with xxxxx xxxxxxx palces I can xxxxxx the xxxxxxxxx xxxxxxx

file1.doc preview (331 words)

xxx (a) Find the critical value from the xxxxxxxxxxx xxxxx distribution xxx x =0.01, x xxx xxx x x xxx

(b) Find the critical xxxxx xxxx the studentized xxxxx distribution for x =0.05, v 12, xxx x = xxx

(c) Find xxx critical xxxxx from the xxxxxxxxxxx range xxxxxxxxxxxx for x =0.05, v xxx and x = 18

(d) Find the critical value xxxx xxx studentized range xxxxxxxxxxxx xxx H0: µ1= µxx µ3= µxx µxx with xxxx xx x x xxxxxx

(a) x…7.65…..) xxxxxx to xxxxx decimal xxxxxx as xxxxxxxx

xxx (…xxxx…xxxxxxxx xx xxxxx xxxxxxx places as xxxxxxxx

(c) (…5.92…xxx (Round to three xxxxxxx places as needed)

(d) x…5.56….) (Round xx three xxxxxxx xxxxxx as xxxxxxxx

12) xxxx xx xxx xxxxx table.

Source xx variation xxx xx xxxxxxx xxxxxxx of xxxxxxx Mean Squares F-Test Statistic

Treatment 422 4

Error xxxxxxx 23

Total

xxxxxxxx xxx xxxxx table xx filling xx the xxxxxxx xxxxxxxx

xxxxxx of xxxxxxxxx Sum of squares xxxxxxx xx Freedom Mean Squares F-Test Statistic

xxxxxxxxx 422 xx xxxxxxxx) xxxxxxx

xxxxxxxxx xxxxxx 23 (xxxxxxxx

Total

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Answer
Submitted by StatSolver on Sat, 2012-08-04 06:06
teacher rated 26 times
5
purchased one time
price: $30.00

Answer rating (rated one time)

5

Please see the attachment for solution (Question 1 - 10)

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xxxxxx see xxx attachment for solution.The xxxxxxxxx are xx xxx xxxx xxxxxxxx xxx computations xxx xx the Excel file. I have xxxx xxxx the xxxxx xx problems. If you need xxx xxxxxxxxxxxxx please ask me. Thanks.

file1.doc preview (2851 words)

xxxxxx

xxxxxxxxx (a) xxx xxx tastistic, xxx xxx xxxxxxx of xxxxxxxx xxx the critical value xxxxx a=0.05, and xxx the hypothesis xx the a=0.05 level of significance

Outcome A x C D

Observed xx 54 48 53

xxxxxxx 50 xx 50 xxx

xxx PA=PB=PC=PD x ¼

H1: at least xxx xx the xxxxxxxxxxx xx different xxxx xxx xxxxxxx

= (…1.080xxx Round to three decimal places as needed.

There are (…3..) degrees of freedom.

The critical value is (…7.815xxx Round xx xxxxx decimal places xx needed.

Should the xxxx hypothesis be xxxxxxxxxx

xxx xxxxxxx is xxxx than or xxxxx to xxxxx

No because is xxxxxxx than 0.05

xx because 0 is xxxx xxxx or equal xx 0.05

Yes because x is xxxxxxx xxxx 0.05

Answers:

xxxxxxxxxx xxxxxxxxx x 1.080

Degrees of xxxxxxx x 3

xxxxxxxx value x 7.815

C- No because 0 is less than or equal xx 0.05

A xxxxx xxx xxxxxxxxx to xxxxxxxxx the effectiveness xx a certain xxxxxxxxxx A group of xxx patients xxxx xxxxxxxx divided xxxx xxxxxxxxxxxx xxxxx xxx a xxxxxxx group. xxx shows xxx result for xxxxx xxx improvement. xxx xxx xxxxxxxxxxxx group to xx 1 and the xxxxxxx xxxxx xx group 2.

Experimental Control

n 61 51

x xxxx

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file2.xls preview (488 words)

xx

xxxxxxxxxxx
xx xx (Oi-Ei)^2(Oi-Ei)^2/Ei
45 xx 25xxx
54 xxxxxxxx
xx xxx 0.08
xx 50x 0.18
xxxxxxxxxx 1.080
xxx 3
critical xxxxx7.815

Q2

xxxxxxxxxxxxxxxxxxxxxxx
t Test xxx Differences in xxx xxxxx
xxxxxxxx equal population xxxxxxxxxx xbar1 - xxxxx = xxx
xxxxxxxxxxxx xxxxx x1.2351
Hypothesized xxxxxxxxxx0 xxxx xxxxxxxxxx x = xxxxxx
Level of xxxxxxxxxxxxxxxx Degrees of freedom =50
xxxxxxxxxx x Samplep-value x0.0000
xxxxxx xxxx 61 xxxxxxxx xxxxx x2.403
xxxxxx xxxx xxxx
Sample Standard Deviation 6.4xxx confidence interval
Population x xxxxxx ta/2 x xxxxx
Sample Size51 Lower bound x5.319
xxxxxx xxxx 3.4Upper bound x10.281
xxxxxx xxxxxxxx xxxxxxxxx 6.6

xx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
xxxx -3.6167
Initial After5Years xxxx xx 4.5814
62.7 66.5 xxxx x 6
72.9 xxxx -3.3xxxxxxxx error x 1.8704
xxxx38.8 -2.6 xxxx statistic, x x-1.9337
xxxx xxxxxxxxdf xx
xxxx 62.9xxxxxxxxxxx value xxxxxxxx
xxxx 58.8-8.2 xxxxxxx =0.0555
xxx confidence xxxxxxxx
xxxx =xxxxx
Lower bound = xxxxxx
xxxxx xxxxx =1.191
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file3.xls preview (361 words)

xxxxxx

xxxxxxxxxxxxxxxxxxxxx
PR10R17.5A7.5 A12.5
xxxx 37 xx 80
xx xx 85 72xxx
33xxxx82 81
58xx45 92 xx
28 83 xxxxxx
70 69xxxx 91
2557 xxx70xx

xxxxx

xxxxxxxxxxxxxxxxxxxxxx
Anova: Single xxxxxx
SUMMARY
Groups CountSum xxxxxxx Variance
x 7 xxx 40 355.3333333333
R107 486xxxxxxxxxxxxx320.2857142857
xxxxxxxxx 70.8571428571 xxxxxxxxxxxxxx
A7.5 x xxx xxxxxxxxxxxxx xxxxxxxxxxxxxx
xxxxx7 xxx xxxxxxxxxxxxxxxxxxxxxxxxxxx
ANOVA
Source xx xxxxxxxxx xx xx xx xxxxxxxxx xxxx
xxxxxxx Groupsxxxxxxxxxxxxxxx 41910.0285714286 xxxxxxxxxxxx xxxxxxxxxxxx 2.6896316285
xxxxxx xxxxxxxxxxxxxxxxxxxxxx 30334.9428571429
xxxxx xxxxxxx 34

TukeyKramer

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Tukey Kramer xxxxxxxx xxxxxxxxxxx
Samplexxxxxx xxxxxxxxxxxx xxxxx xxxxxxxx
xxxxxxxxxSize xxxxxxxxxxxxxxxxxxxx of xxxxxxxxxxRange xxxxxxx
xxxx Group 1 xx Group 2 xxxxxxxxxxxxx 6.9172956849xxxxxxxxxxxxx xxxxx are xxxxxxxxx
x69.4285714286 xxxxxx x xx xxxxx 3 xxxxxxxxxxxxxxxxxxxxxxxxx28.3609123079xxxxx are xxxxxxxxx
3 70.8571428571 7Group 1 xx Group 4 xxxxxxxxxxxxxxxxxxxxxxxxx 28.3609123079xxxxx xxx xxxxxxxxx
471.85714285717 xxxxx 1 xx Group 5xxxxxxxxxxxxx6.9172956849 28.3609123079 Means are xxxxxxxxx
x xxxxxxxxxxxxx xxxxxx x xx Group xxxxxxxxxxxxxxxxxxxxxxxxx28.3609123079 xxxxx xxx not different
Group 2 xx xxxxx 42.4285714286 xxxxxxxxxxxx28.3609123079xxxxx xxx xxx different
Other Data Group x xx xxxxx 5 15.42857142866.917295684928.3609123079xxxxx xxx not different
Level xx significancexxxx Group 3 to xxxxx x x6.917295684928.3609123079 xxxxx xxx xxx xxxxxxxxx
Numerator xxxx5xxxxx 3 xx Group 5 146.9172956849xxxxxxxxxxxxx Means are xxx different
xxxxxxxxxxx d.f. 30 Group x xx Group xxx6.9172956849 28.3609123079 xxxxx are not xxxxxxxxx
xxx 334.9428571429
x

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Answer
Submitted by shahimermaid on Sat, 2012-08-04 10:03
teacher rated 224 times
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price: $5.00

Q1, 11,12,13 with full explanation

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I xx xxxxx xxx rest xxx xxxx post soon

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http://www.homeworkmarket.com/content/hwk-2

xxxxxxxxx xxx xxx xxx statistic, xxx the degrees xx freedom, xxx xxx xxxxxxxx xxxxx xxxxx a=0.05, xxx (d) xxx hypothesis at xxx a=0.05 xxxxx xx xxxxxxxxxxxx

xxxxxxxxxxxxxxxxxxx

Outcome

xxxxxxxx

Expected

(O — xx

xx — xxx

xx — xxxx x

x

xx

50

xx

25

0.5

x

xx

xx

x

16

0.32

x

48

xx

xx

x

0.08

x

xx

50

3

9

xxxx

1.26

Degrees of xxxxxxx = (2 x 1)(4- xx x 1(3) x 3

xxx xxxxxxxxxxx x ¼

xxx at least xxx xx the xxxxxxxxxxx xx different from xxx others.

x (1.26) xxxxx to xxxxx decimal xxxxxx xx needed.

There xxx xxx xxxxxxx of xxxxxxxx

The critical value is (7.815) xxxxx xx three decimal xxxxxx xx xxxxxxx

Should the null hypothesis xx xxxxxxxxx

Yes xxxxxxx is xxxx xxxx xx equal xx xxxx

xx xxxxxxx is xxxxxxx xxxx 0.05

No because x xx xxxx xxxx or equal xx xxxx

xxx xxxxxxx 0 is greater than 0.05

Accept Ho because 1.26 is smaller than 7.815 (for xxxxx 

xxx xxxxxx xxxxxxxxxxxx table.

probability level

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