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Question
Submitted by Dadato on Thu, 2012-07-19 20:33
due on Sat, 2012-07-21 20:30
answered 1 time(s)
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Please can anyone help me with my homework?

Thanks!

Koku

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Answer
Submitted by StatSolver on Fri, 2012-07-20 13:29
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Please see the attachment for solution.

body preview (33 words)

xxxxxx see xxx attachment for solution. xx xxx xxxx xxx xxxxxxx clarification please xxx me. The answers xxx given xx the word document and xxx xxxxxxxxxxxx xxx xxxxx xx xxx Excel xxxxx Thanks.

file1.doc preview (3291 words)

xxx xxxx and alternative xxxxxxxxxx are giving. Determine xxxxxxx the xxxxxxxxxx xx left xxxxxxx xxxxx tailed; xx two tailed. xxxx xxxxxxxxx xx being tested?

H0: p= xxxxx

xxxx> 0.76

xxxxx the correct xxxxxx xxxxxx

x Left xxxxxxx

xxxxxx xxxxxxx

xxxx xxxxxxx

Answer: Right tailed

xxxx parameter is xxxxx xxxxxxxx

xxxxxxx

xxµ

c-p

Answer: c-p

xxxx xxx hypothesis xxxxx xxx xxxxxxxxx approach xxx xxx xxxxxxx approach.

H0: p=0.45 versus xxx x<xxxxx

xxxxxx x=62, a=0.05

xxxxxxx xxx xxxx using xxx classical xxxxxxxxx choose xxx correct answer below.

_Reject xxx xxxx xxxxxxxxxxx

_There xx xxx xxxxxx information xx test the xxxxxxxxxxx

_Do not xxxxxx xxx null hypothesis

Answer: Do xxx reject xxx null hypothesis

xxxxxxx xxx xxxx using xxxxxxx xxxxxxxxxx

xxxxxxx =…xxxxxx…. (Round to four xxxxxxx xxxxxx as xxxxxxxx

xxxxxx the correct xxxxxx xxxxxxx

_ xxxxxx the null xxxxxxxxxxx

xxxxxx xx xxx xxxxxx xxxxxxxxxxx xx xxxx the hypothesis

xxx not xxxxxx the xxxx xxxxxxxxxx

Answer: xxxxxxx = 0.1834x Do

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file2.xls preview (724 words)

xx

xxxxxxxxxxxxxx
Z Test of Hypothesis for the xxxxxxxxxx
xxxx
xxxx xxxxxxxxxx p=0.45
Level of Significance xxxx
Number xx Successes 62
Sample xxxx150
xxxxxxxxxxxx Calculations
Sample Proportion0.4133333333
Standard Error0.040620192
Z xxxx xxxxxxxxx xxxxxxxxxxxxx
Lower-Tail Test
xxxxx xxxxxxxx Value -1.6449
p-Value0.1834
xx xxx xxxxxx the xxxx xxxxxxxxxx

xx

xxxxxx
xxxxxx Size xxxxxxxxxxxxx
xxxx
xxxxxxxx xx xxxx xxxxxxxxxx xxxx
xxxxxxxx Error0.02
xxxxxxxxxx xxxxx 94%
xxxxxxxxxxxx xxxxxxxxxxxx
Z Value -1.8807926501
Calculated xxxxxx Size xxxxxxxxxxxxxxx
Result
Sample Size Needed 2210

xx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Confidence xxxxxxxx Estimate xxx xxx xxxx xxxxxxxxxx Interval Estimate for the xxxx xxxxxxxxxx xxxxxxxx xxxxxxxx xxx the Mean
xxxx xxxx Data
Sample Standard Deviation10 xxxxxx xxxxxxxx Deviation xx Sample xxxxxxxx xxxxxxxxx xx
Sample xxxx 107 Sample xxxx107 xxxxxx xxxx 107
Sample Size xx Sample xxxxxx xxxxxx Size14
Confidence Levelxxx xxxxxxxxxx xxxxx xxx Confidence xxxxx96%
xxxxxxxxxxxx xxxxxxxxxxxxIntermediate CalculationsIntermediate xxxxxxxxxxxx
xxxxxxxx Error xx xxx xxxxxxxxxxxxxxxxxxxxxxxx xxxxx of the Mean 1.9611613514 Standard xxxxx of xxx xxxx 2.6726124191
Degrees xx xxxxxxx13 Degrees xx xxxxxxx 25 Degrees of xxxxxxxxx
x Valuexxxxxxxxxxxxt xxxxxxxxxxxxxxxxxt Value 2.2816038836
xxxxxxxx Half xxxxx5.7738269877 Interval xxxx xxxxx xxxxxxxxxxxx Interval Half xxxxx6.0978428748
Confidence

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