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Question
Submitted by jhebae on Tue, 2012-05-01 14:56
due on Sat, 2012-05-05 14:56
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In a cross between a pea plant that has smooth yellow seeds (SsYy) with a second plant of the same...

In a cross between a pea plant that has smooth yellow seeds (SsYy) with a second plant of the same genotype, what proportion of the seeds will grow up to produce smooth green seeds? A. 0/16 B. 3/16 C. 9/16 D. 16/16

Answer
Submitted by Coloratus on Wed, 2012-05-02 14:01
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Crossing xxxx with SsYy we xxxx

xxxxxxxxxxxx

xxxx

SSYy

SSYy

SSyy

SsYY

xxxx

SsYy

xxxx

SsYY

SsYy

xxxx

xxxx

ssYY

ssYy

ssYy

ssyy

xxxx xxxxxx

xxxxx smoothness xx dominant, and xxxxx xxxxx are xxxxxxxxxx we search xxx genotypes that have:

xxx xx Ss

xxx

And those xxxx

xxxxxxx

SSYY

xxxx

xxxx

xxxx

xxxx

SsYy

SsYy

xxxx

xxxx

SsYy

xxxx

xxxx

ssYY

ssYy

ssYy

ssyy

We xxx that the ratio is:

B. 3/16


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Answer
Submitted by rajendrabnk on Wed, 2012-05-02 01:52
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answer with explanation is attached.

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DONT forget to give xxxxxx if you xxxxx xxx answer.

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The answer xx xx 3/16.

P1 SMOOTH, YELLOW x xxxxxxxxx green

xxxxxxxxxx SSYY xxxx

gametes: SY sy

                  

F1 xxxxxxx YELLOW x xxxxxx xxxxxx

genotypes: SsYy  X  xxxx 

gametes: xxx xxx sY, xx

F2

A xxxxxxx rule for xxxxxxxx crosses xxxxx  x  xxxxx

TRAIT xx xxxxx x X xxxxx 1, xxxxx 2         xxxxxx xxxx xxxxxx are xxxxxxxxx

9 x xxxxx 1 and TRAIT 2 expressed (A-B-)

x x TRAIT x expressed (A-bb)

3 x xxxxx 2 expressed (aaB-)

x - No xxxxxxxx traits expressed (all aabb)

9:3:3:1 can be xxxxxxxx xx a dihybrid xxxxx by xxxxx xxxxxxxxxxx probabilities for two xxxxxxxxxx crosses and then combining their xxxxxxxxxxxxxx

xxxxxxxxxxx of smooth x 3/4

probability of wrinkled = 1/4

xxxxxxxxxxx of yellow = 3/4

xxxxxxxxxxx xx green = xxx

 

xxxxxxxxxxx xx xxxxxx and xxxxxx = xxx x 3/4 x xxxx

probability xx smooth xxx green = xxx x 1/4 = 3/16

xxxxxxxxxxx xx xxxxxxxx and yellow x 1/4 x 3/4 = 3/16

xxxxxxxxxxx of xxxxxxxx and green x 1/4 x 1/4 = xxxx


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