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Question
Submitted by Jdpt3 on Tue, 2012-06-12 20:09
due on Tue, 2012-06-12 20:07
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Statistics

Business Statisticks

Business Statistics

Second Exam

Instructions: Answer the following four questions. Write legibly and show all work. Begin each numbered question on a fresh page. Unsupported answers will receive zero points. You must work independently.

Due: Tuesday 6/12, 11:59pm

1. Sears rates its salespersons according to their sales ability and their potential for advancement. They sampled 500 salespeople with following data:

(a) Calculate the probability that a randomly selected Sear's salesperson has above average sales ability and is an excellent potential for advancement?

(b) Calculate the probability that a randomly selected Sear's salesperson will have average sales ability an and good potential for advancement?

(c) Calculate the probability that a randomly selected Sear's salesperson will have below average sales ability and fair potential for advancement?

(d) Calculate the probability that a randomly selected Sear's salesperson will have an excellent potential for advancement given they also have above average sales ability?

(e) Calculate the probability that a randomly selected Sear's salesperson will have an excellent potential for advancement given they also have average sales ability?

2.A study by the Information Technology department at WPU revealed company employees receive an average of four e-mails per hour. Assume the arrival of these e-mails is approximated by the Poisson distribution.

(a) What is the probability , Prof. Smith, received exactly one e-mail between 4pm and 5pm yesterday?

(b) What is the probability he did not receive any e-mail during this period?

(c) What is the probability he received ten or more e-mails during the same period?

3. A recent study in NJ showed that 50% of all patients will return to the same dentist. Suppose nine patients are selected at random, what is the probability that:

(a) Exactly five of the patients will return?

(b) All nine will return?

(c) At least eight will return?

(d) At least one will return?

(e) How many patients would be expected to return to the same dentist, i.e., what is the mean of the distribution?

4. A recent study of long distance phone calls made from WPU, showed that the length of the calls follows the normal probability distribution with a mean of 3.2 minutes per call and a standard deviation of 0.50 minutes.

(a) What fraction of the calls last between 3.2 and 4 minutes?

(b) What fraction of the calls last more than 4 minutes?

(c) What fraction of the calls last between 4 and 4.5 minutes?

(d) What fraction of the calls last between 3 and 4.5 minutes?

Answer
Submitted by StatSolver on Tue, 2012-06-12 21:13
teacher rated 56 times
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Answer rating (rated one time)

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Please see the attachment for solution. If you need any clarification please ask me. Thanks.

body preview (15 words)

Please xxx the xxxxxxxxxx for xxxxxxxxx xx you xxxx xxx xxxxxxxxxxxxx please xxx xxx Thanks.

file1.doc preview (832 words)

1. Sears xxxxx xxx xxxxxxxxxxxx according xx xxxxx xxxxx xxxxxxx xxx xxxxx xxxxxxxxx for xxxxxxxxxxxx xxxx sampled xxx salespeople with following xxxxxx

xxxxxxxxxxxxx

Fair

xxxx

xxxxxxxxx

Total

xxxxx average

16

xx

xx

xx

stability xxxxxxx

xx

xx

45

150

below xxxxxxx

93

xx

135

300

xxxxx

154

144

xxx

500

xxx xxxxxxxxx xxx xxxxxxxxxxx that a randomly selected Sear's salesperson xxx xxxxx xxxxxxx xxxxx xxxxxxx xxx is xx excellent xxxxxxxxx for xxxxxxxxxxxx

P(Above xxxxxxx and Excellent) = 22/500 = xxxxx

(b) xxxxxxxxx the probability xxxx x randomly selected xxxxxx salesperson will xxxx average sales xxxxxxx an xxx xxxx xxxxxxxxx for advancement?

P(Stability xxxxxxx xxx Good) = 60/500 = 0.12

(c) Calculate the probability xxxx x randomly selected xxxxxx xxxxxxxxxxx will have xxxxx xxxxxxx xxxxx xxxxxxx xxx xxxx xxxxxxxxx for advancement?

xxxxxxxx xxxxxxx xxx xxxxx = xxxxxx x xxxxx

(d) Calculate xxx xxxxxxxxxxx that a randomly xxxxxxxx xxxxxx salesperson xxxx

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file2.xls preview (69 words)

Sheet1

xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx
Poisson distributionBinomial distributionxxxxxx xxxxxxxxxxxx
x xxxxxxxxxxxxx x x P(Z < xx
0xxxxxx xxxxxxxxxxx0 xxxxxxxxxxxx
xxxxxxx 10.0176xxxx0.9452
x xxxxxx x xxxxxx 4.52.6xxxxxx
3 xxxxxx3xxxxxx 3 -0.4xxxxxx
4 xxxxxx 4xxxxxx
x xxxxxx 50.2461
60.10426 xxxxxx
7 xxxxxx x0.0703
x xxxxxx x0.0176
90.0132 x xxxxxx
xxxx Goodxxxxxxxxxxxxxx
Above average1612xx50
xxxxxxxxx average xx xx xx150
xxxxx average9372135 300
xxxxx 154 144 xxx 500


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Answer
Submitted by Kumail Raza on Wed, 2012-06-13 09:13
teacher rated 24 times
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price: $39.95

Answer file with formula and step by step calculation with printable format is attached. Feel free to contact for any further assistance.

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file1.xlsx preview (1199 words)

xx

xxxxxxxxxxxxxxxxxxxxxxxxxxxxx
xxxxxxxxxxxxxxxx xxx advancement
xxxxx xxxxxxxFairxxxxxxxxxxxxxxxxxx
F G xI
xxxxx xxxxxxx5 xx xxxxxx
average 6 xx60 xxxxx
xxxxx averagex xx xxxxx xxx
xxxxx xxxx xxx 202 500
xxxxxxxxx
xxx xxxxxxxxx the probability that x xxxxxxxx selected Sear’s salesperson has above average xxxxx xxxxxxx and xx xx xxxxxxxxx xxxxxxxxx xxx xxxxxxxxxxxx 
xxxxxxx0.27
(b) Calculate xxx probability that a xxxxxxxx xxxxxxxx xxxx’s salesperson xxxx have average xxxxx ability an and xxxx xxxxxxxxx for advancement? 
=G6/I8 = 0.12
(c) xxxxxxxxx xxx xxxxxxxxxxx xxxx a randomly xxxxxxxx xxxx’s xxxxxxxxxxx xxxx have xxxxx average xxxxx xxxxxxx xxx fair potential xxx advancement? 
=F5/I8x xxxx
(d) Calculate xxx xxxxxxxxxxx that x xxxxxxxx xxxxxxxx Sear’x

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Answer
Submitted by shahimermaid on Wed, 2012-06-13 05:13
teacher rated 378 times
4.34656
price: $35.00

the answer is in attached file

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file1.docx preview (448 words)

xxxxx xxxxx xxx salespersons xxxxxxxxx xx xxxxx sales ability xxx xxxxx xxxxxxxxx xxx advancement. They sampled 500 xxxxxxxxxxx with xxxxxxxxx data:

xxx Calculate xxx probability xxxx x randomly selected Sear's xxxxxxxxxxx xxx xxxxx xxxxxxx xxxxx ability and is an excellent potential for advancement? xxxxxxxx =0.27

(b) Calculate xxx probability that a randomly selected xxxxxx xxxxxxxxxxx will have average xxxxx xxxxxxx and good potential for xxxxxxxxxxxx =60/500=0.12

(c) Calculate xxx xxxxxxxxxxx that x xxxxxxxx xxxxxxxx xxxxxx xxxxxxxxxxx xxxx xxxx xxxxx average sales xxxxxxx and fair xxxxxxxxx for advancement? =16/500=0.032

xxx xxxxxxxxx xxx probability that x randomly selected Sear's salesperson will xxxx an xxxxxxxxx xxxxxxxxx xxx xxxxxxxxxxx xxxxx xxxx xxxx have above xxxxxxx sales ability? =135/(93+72+135)=0.45

xxx xxxxxxxxx xxx xxxxxxxxxxx xxxx a xxxxxxxx selected Sear's salesperson will xxxx xx xxxxxxxxx potential xxx xxxxxxxxxxx given xxxx also xxxx xxxxxxx xxxxx xxxxxxxx =

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