# Balance the assembly Line (Operations Managment)

Balance the assembly line for the tasks contained in the table. The desired output is 240 units per day. Available production time per day is 480 minutes.

Work Element Time (Sec.) Immediate Predecessor(s)

A 40 ---

B 45 ---

C 55 A

D 55 B

E 65 B

F 40 C,D

G 25 D,E

a) What is the desired Cycle time in seconds?

b) What is the theoretical minimum number of stations?

c) Use trial and error to work out a solution in the table below. Your efficiency should be at least 90%.

Station Candidates Choice Work-Element

Time (Sec) Cumulative Time (Sec) Idle Time

d) Calculate the efficiency of your solution.

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4. xxxxxxx the xxxxxxxx line xxx the tasks xxxxxxxxx in the table. xxx desired output xx 240 units per xxxx Available production xxxx xxx day xx xxx xxxxxxxx

xxxxxxxxxxxxWork Element | xxxx (Sec.) | Immediate Predecessor(s) |

x | xx | --- |

B | 45 | xxx |

x | xx | A |

D | xx | B |

x | 65 | x |

F | xx | xxx |

G | 25 | xxx |

xxxx xx xxx desired xxxxx time xx xxxxxxxx xx xxxxxxx

xxxxxxxx

Production time xxx day x xxx xxxxxxx = 8 hours

xxxxxxx output xxxxxxx xx 240 xxxxx xxx day x xxxxx = xx units xxx xxxx

xxxxxx desired xxxxx xxxx in seconds is given xx

c x 3600/30 x **120 **xxxxxxx xxx unit.

What xx xxx theoretical xxxxxxx number xx xxxxxxxxx xx xxxxxxx

Answer:-

Theoretical minimum, TM = xxxx xx xxx xxxxx xx

x xxxxxxxxxxxxxxxxxxxxxxxxxx

x xxxxxxx x xxxx

**xxxxxx xxxxxxxxxxx xxxxxxx xxx xx stations is 3.**

xxx xxxxx xxx xxxxx to xxxx xxx x solution xx xxx xxxxx below. Your efficiency should be at xxxxx xxxx xxx xxxxxxx

xxxxxxxx

For 1st station start with x

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xxxxxx xxx xxx attachment xxx solution. If xxx need xxx xxxxxxxxxxxxx please xxx me. xxxxxxx

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xx xxxxxxx the xxxxxxxx xxxx xxx xxx tasks contained xx xxx xxxxxx The xxxxxxx output is 240 units per day. xxxxxxxxx production xxxx per xxx xx xxx minutes.

xxxxxxxxxWork Element | xxxx (Sec.) | xxxxxxxxx xxxxxxxxxxxxxx |

x | xx | --- |

x | 45 | --- |

C | xx | A |

D | xx | B |

x | xx | x |

F | xx | xxx |

x | xx | D,E |

a) xxxx is the desired xxxxx xxxx xx xxxxxxxx xx points)

Cycle time xx xxxxx by,

xxx xx = x xxxx minutes/240 xxxxxxxxx seconds/minute)

xxxx = **120** xxxxxxxxxxxxx

b) xxxx xx xxx xxxxxxxxxxx minimum xxxxxx of stations? xx xxxxxxx

xx

xxxx theoretical minimum xxxxxx xx xxxxxxxx is given xxxx

xxxxxx = = xxx x xx + 55 x 55 + xx + 40 x xxxxxxx

xxxx x xxxxxxxx

xxxx = xxxxxx or **3** xxxxxxxxx

xx Use xxxxx and xxxxx to xxxx out a solution xx the xxxxx below. xxxx efficiency xxxxxx xx at xxxxx 90%. (10 xxxxxxx

xxxx xxxxxxxxxx diagram is xxxxx in xxx xxxxxxxxx figure.

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xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx | Candidates | xxxxxx | xxxxxxxxxxxxx xxxx xxxxx | xxxxxxxxxx xxxx xxxxx | Idle Time (c x 120) |

xx | B | B | xx | 45 | xx |

A,D,E | E | xx | xxx | 10 | |

S2 | x | A | xx | 40 | xx |

x | C | xx | xx | xx | |

S3 | xxxxx | D | xx | 55 | xx |

F,G | x | xx | xx | xx | |

x | x | xx | 120 | x |

S1 x {B,E}, S2 = {A, C}, xxx S3 x {D, F, xx

xx Calculate the efficiency xx your solution. (2 xxxxxxxx

The efficiency of xxx solution is given by,

Efficiency =

= [325/(3*120)](100%)

x (325/480)(100%)

x (0.9028)(100%)

= **xxxxx** %

Balance delay = xxxx - xxxxxxxxxx x xxxx x 90.28% x xxxxx

40

A

xx

E

45

B

25

x

55

x

5530

x

xxx

x

# xxxxxxxxxxxxxxxxxxx

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# xxxxxxxxxxxxxxxxxxx

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